A. 3P
B. P/3
C. 3P/T
D. 6P
¨ This relationship between the pressure, volume, and temperature of a gas is described by Boyle’s law, which states that the product of the pressure and volume of a gas is constant at a constant temperature. Mathematically, Boyle’s law can be expressed as: P1V1 = P2V2
¨ Where P1 and V1 are the initial pressure and volume, respectively, and P2 and V2 are the final pressure and volume, respectively.
¨ In this case, the temperature is constant, and the initial and final masses of the gas are the same. Therefore, we can use Boyle’s law to relate the initial and final pressures and volumes:
¨ P1V1 = P2V2
¨ If V2 = 3V1, then:
¨ P1V1 = P2(3V1) P1 = P2/3
¨ Therefore, the final pressure P2 will be 1/3 times the initial pressure P1, or P2 = P1/3. Hence, the correct answer is option B, P/3.
Submitted by :- Jamil Ahmed