A. hydrogen ion
B. hydride ion
C. oxide ion
D. methoxide ion
¨ The Cannizzaro reaction involves the transfer of electrons rather than ions. Specifically, the reaction involves the transfer of a hydride ion (H-) from one molecule of the aldehyde to the carbonyl carbon of another molecule of the same aldehyde, in the presence of a strong base such as sodium hydroxide (NaOH) or potassium hydroxide (KOH).
¨ During the reaction, one molecule of the aldehyde is oxidized to the corresponding carboxylic acid, while the other molecule is reduced to the corresponding alcohol. The hydride ion acts as a reducing agent, while the base acts as a catalyst and a proton acceptor.
| Ø The Cannizzaro reaction is a redox reaction that involves the oxidation of one molecule of an aldehyde and the reduction of another molecule of the same aldehyde, in the presence of a strong base such as sodium hydroxide (NaOH) or potassium hydroxide (KOH). The reaction results in the formation of an alcohol and a carboxylic acid as the two main products.
Ø The general equation for the Cannizzaro reaction can be written as follows: RCHO + RCHO + 2 NaOH → RCOOH + RCH2OH + Na2CO3 |
Submitted by :- Jamil Ahmed