If a compound contains 24 gram of carbon 2 gram of hydrogen and 64 gram of oxygen then its empirical formula will be________?

First, we need to convert the given masses into moles using their respective atomic/molecular weights:

·    Moles of carbon: 24 g / 12.01 g/mol = 1.999 ≈ 2

·    Moles of hydrogen: 2 g / 1.01 g/mol = 1.98 ≈ 2

·    Moles of oxygen: 64 g / 16.00 g/mol = 4

The mole ratios are therefore C:2, H:2, O:4. To simplify the ratios, we can divide each of them by the smallest, which is 2:

·    C:2/2 = 1

·    H:2/2 = 1

·    O:4/2 = 2

So the empirical formula is CHO2. Therefore, the answer is D.